Chapter+2+linear+Equations+and+functions

=Slope Intercept form= =Graphing slope intercept= =Linear Inequalities in two variables=
 * Slope**
 * to find the slope of two plotted points on a graph you have to use m=y2-y1/x2-x1
 * so if the problem is 4,3 and 2,2 then you would have to do m=3-2/2-4. the answer would be m=1/2 which would be your answer
 * the linear equation of slope-intercept form is y=mx+b, m is the slope and b is the y-intercept.
 * in the problem 2x+3y=12, you would first move 2x to the other side making the problem 3y=-2x+12. Finally you would divide by 3 making it y=-2/3+4.
 * to graph a problem in slope intercept form you must first find the y-intercept and then graph the slope.
 * i will use our equation from the last part y=-2/3+4. you would first go up 4 on the y axis and plot your point. then you would plot the slope using rise/run which would be -2/3 from 4 on the y axis. then you would draw a straight line through both points.
 * to solve linear inequalities you must make the form true. examples of different forms are Ax+ByC, Ax+By__>__C
 * if the problem was 5x+6y>12 then x and y would have to be 1 or else the statement would not be true because they would go over 12.